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7x^2-19x-20008=0
a = 7; b = -19; c = -20008;
Δ = b2-4ac
Δ = -192-4·7·(-20008)
Δ = 560585
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{560585}}{2*7}=\frac{19-\sqrt{560585}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{560585}}{2*7}=\frac{19+\sqrt{560585}}{14} $
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